Question

CH₂ = CH – CH = CH₂$\underset{1equiv.}{\overset{\quad H_{2}/Pt\quad}{\rightarrow}}A\overset{\quad O_{3}/H_{2}O\quad}{\rightarrow}B$

A and B are

• A. CH₃ – CH₂ – CH = CH₂, (CH₃CH₂COOH + CO₂)
• B. CH₃ – CH = CH – CH₃, CH₃COOH (2 mol)
• C. CH₃ – CH = CH – CH₃, CH₃CHO (2 mol)
• D. CH₃ – CH₂ – CH = CH₂, (CH₃CH₂CHO + HCHO)

Answer 1

Answer: (B)

CH₃ – CH = CH – CH₃, CH₃COOH (2 mol)

Answer 2

$\underset{\mathbf{(A)}}{\mathbf{C}\mathbf{H}_{\mathbf{3}}\mathbf{-}\mathbf{CH = CH}\mathbf{-}\mathbf{C}\mathbf{H}_{\mathbf{3}}}$

$\xrightarrow { \mathrm { O } _ { 3 } / \mathrm { H } _ { 2 } \mathrm { O } }$ $\underset{\mathbf{(B)}}{\mathbf{2C}\mathbf{H}_{\mathbf{3}}\mathbf{COOH}}$

[Zinc is not present hence CH₃CHO first formed is oxidised to CH₃COOH)