Solveeit Logo

Question

Question: Chords of an ellipse are drawn through the positive end of the minor axis. Then locus of mid point o...

Chords of an ellipse are drawn through the positive end of the minor axis. Then locus of mid point of chords must be

A

A circle

B

A parabola

C

An ellipse

D

A hyperbola

Answer

An ellipse

Explanation

Solution

x2a2\frac{x^{2}}{a^{2}}+ y2b2\frac{y^{2}}{b^{2}} = 1;equation of chord in mid-point

form T= S1

hxa2\frac{hx}{a^{2}} + kyb2\frac{ky}{b^{2}} – 1 = h2a2+k2b2\frac{h^{2}}{a^{2}} + \frac{k^{2}}{b^{2}} – 1

it is passes through (0, b) ; 0 + kb\frac{k}{b} = h2a2\frac{h^{2}}{a^{2}} + k2b2\frac{k^{2}}{b^{2}}

locus of (h, k) is x2a2\frac{x^{2}}{a^{2}} + y2b2\frac{y^{2}}{b^{2}}yb\frac{y}{b} = 0

which is again a ellipse.