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Question

Physics Question on mechanical properties of solids

Choose the correct relationship between Poisson ratio (σ)(\sigma), bulk modulus (K)( K ) and modulus of rigidity (η)(\eta) of a given solid object :

A

σ=3K+2η6K+2η\sigma=\frac{3 K+2 \eta}{6 K+2 \eta}

B

σ=6K2η3K2η\sigma=\frac{6 K-2 \eta}{3 K-2 \eta}

C

σ=3K2η6K+2η\sigma=\frac{3 K-2 \eta}{6 K+2 \eta}

D

σ=6K+2η3K2η\sigma=\frac{6 K+2 \eta}{3 K-2 \eta}

Answer

σ=3K2η6K+2η\sigma=\frac{3 K-2 \eta}{6 K+2 \eta}

Explanation

Solution

The correct answer is (C) : σ=3K2η6K+2η\sigma=\frac{3 K-2 \eta}{6 K+2 \eta}
Y=3η(1+σ)
Y=3K(1−σ)
⇒2η(1+σ)=3K(1−2σ)
⇒σ=(6K+2η3K−2η​)