Question

Choose the correct option.
${\text{A Ca(HC}}{{\text{O}}_{\text{3}}}{{\text{)}}_{{\text{2}}}}{\text{ + B Ca(OH}}{{\text{)}}_{\text{2}}} \to {\text{C CaC}}{{\text{O}}_{\text{3}}}{\text{ + D }}{{\text{H}}_{{\text{2}}}}{\text{O}}$
This question has multiple correct options
A .A=1
B .B=1
C .C=1
D .D=2

Answer 1

When atoms gain or lose electrons to form ions, or when they join with other atoms to form molecules, their symbols are changed or combined to produce chemical formulae that accurately reflect these species. Writing and balancing a chemical equation extends this symbology to express both the identities and relative amounts of substances experiencing a chemical (or physical) change.

Complete answer:
To begin, identify the components on the reactant side (left side) and the compound elements on the right side (right side).
As shown above, construct a list of all the components on either side of the equation for both the reactants and products.
An atom is the smallest component of an element, containing all of the element's chemical characteristics. Each element's atom contains the element's protons, neutrons, and electrons.
The list of each element, both on the reactant and product sides, can help you figure out how many atoms each element has.
Take note of how the number of atoms adjacent to each element differs from the number of atoms adjacent to the identical element on the product side.
You must ensure that the number of atoms of each element on the reactant side equals the number of atoms of each element on the product side in order to balance the chemical equation. To make both sides equal, increase the number of atoms in each element until they are equal on both sides.
You'll add the number, the coefficient, of how much you multiplied the element by in front of that element or compound in the equation after you've multiplied the number of atoms of each element until both sides are equal.
Make a list of elements again after you've set the coefficients in front of the molecules, and see whether multiplying the coefficient with the subscript gives you atoms that are identical on both the reactant and product sides.

| LHS| RHS| MULTIPLICATION FACTOR
---|---|---|---
Ca| 2| 1| 2 IN RHS
H| 4| 2| 2 IN RHS

The rest of the carbon and oxygen will get automatically balanced.
Hence ${\text{1 Ca(HC}}{{\text{O}}_{\text{3}}}{{\text{)}}_{{\text{2}}}}{\text{ + 1 Ca(OH}}{{\text{)}}_{\text{2}}} \to 2{\text{ CaC}}{{\text{O}}_{\text{3}}}{\text{ + 1 }}{{\text{H}}_{{\text{2}}}}{\text{O}}$is the correct answer which means option A B D are correct.

Note:
Because it does not explicitly reflect the ionic species that are present in solution, this balanced equation is referred to as a molecular equation. When ionic compounds dissolve in water, they may dissociate into their constituent ions, which are then uniformly disseminated throughout the solution (a thorough discussion of this important process is provided in the chapter on solutions).