Question

Choose the correct option

Molecule	Shape
A	$BrF_5$
B	$H_2O$
C	$ClF_3$
D	$SF_4$

• A. (A)- IV, (B)- III, (C)- I, (D)- II
• B. (A)- III, (B)- IV, (C)- I, (D)- II
• C. (A)- II, (B)- I, (C)- III, (D)- IV
• D. (A)- I, (B)- III, (C)- IV, (D)- II

Answer 1

Answer: (A)

(A)- IV, (B)- III, (C)- I, (D)- II

Answer 2

Analyze Each Molecule Based on VSEPR Theory:
BrF 5: The molecule has five bonded pairs and one lone pair around bromine, leading to a square pyramidal shape.
H 2O: Water has two bonded pairs and two lone pairs, giving it a bent shape.
ClF 3: Chlorine trifluoride has three bonded pairs and two lone pairs, resulting in a T-shape.
SF 4: Sulfur tetrafluoride has four bonded pairs and one lone pair, leading to a see-saw shape.

Match Each Molecule with the Correct Shape:
(A) BrF5 - Square pyramidal
(B) H2O - Bent
(C) ClF3 - T-shape
(D) SF4 - See-saw

Conclusion: Based on the shapes identified above, the correct answer is Option (1).