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Question

Question: Choose the correct option and justify your choice: \(\sin 2{\text{A}} = 2\sin {\text{A}}\) is true w...

Choose the correct option and justify your choice: sin2A=2sinA\sin 2{\text{A}} = 2\sin {\text{A}} is true when A{\text{A}} is:
(A) 00^\circ
(B) 3030^\circ
(C) 4545^\circ
(D) 6060^\circ

Explanation

Solution

In this question we have to use the formula of sin2A\sin 2{\text{A}} and then we will put this formula in the equation which is given in the question. Now, we will simplify the equation. We also need to remember that the value of cos\cos is 11 when the angle is 00^\circ .

Complete step-by-step solution:
The given equation is sin2A=2sinA\sin 2{\text{A}} = 2\sin {\text{A}} . Now, put the formula sin2A=2sinA cosA\sin 2{\text{A}} = 2\sin {\text{A cosA}} in the equation given in the question and try to simplify it.
Therefore, we can write sin2A=2sinA\sin 2{\text{A}} = 2\sin {\text{A}} as follows:
sin2A=2sinA 2sinA cosA=2sin..(1) \sin 2{\text{A}} = 2\sin {\text{A}} \\\ \Rightarrow 2\sin {\text{A cosA}} = 2\sin {\text{A ……………..(1)}}
Now, just cancel out 2sinA2\sin {\text{A}}from both the sides of the equation (1).(1). Therefore, we will get
cosA=1\Rightarrow \cos {\text{A}} = 1
Now, we know that the value of cos\cos is 11 when the angle A{\text{A}} is 00^\circ i.e. cos0=1\cos 0 = 1
Therefore, we get sin2A=2sinA\sin 2{\text{A}} = 2\sin {\text{A}} when the angle the value of the angle A{\text{A}} is 00^\circ .

Hence, the correct answer is option(A)\left( {\text{A}} \right).

Note: We can also solve the question putting the value of angle A{\text{A}} available in the options.
If we put the value of angle A=0{\text{A}} = 0^\circ in the equation sin2A=2sinA\sin 2{\text{A}} = 2\sin {\text{A}} . Then we will get
sin2(0)=2sin(0) sin0=2sin0 0=0 \sin 2\left( {0^\circ } \right) = 2\sin \left( {0^\circ } \right) \\\ \Rightarrow \sin 0^\circ = 2\sin 0^\circ \\\ \Rightarrow 0 = 0
Therefore, we are getting the same answer by using different methods.
Hence, the correct answer is option (A)\left( {\text{A}} \right).