Question

Chloromethane on treatment with excess of ammonia yields mainly

• A.
• B. $N$-methylmethanamine $(CH_3??H??H_3)$
• C. methanamine $(CH_3NH_2)$
• D. mixture containing all these in equal proportion

Answer 1

Answer: (C)

methanamine $(CH_3NH_2)$

Answer 2

$\underset{\text{Chloromethane}}{ {CH3Cl}} +$ $\underset{\text{(excess)}}{ {NH3}} {->}$ $\underset{\text{Methanamine}}{ {CH3NH2}} {+ HCl}$ Primary amine is obtained as a major product by taking large excess of ammonia.