Question
Chemistry Question on Aromatic Hydrocarbon
Chiral complex from the following is
Here en = ethylene diamine
A
trans – [Co(NH3)4Cl2] +
B
cis – [PtCl2(en)2] 2+
C
cis – [PtCl2(NH3)2]
D
trans – [PtCl2(en)2] 2+
Answer
cis – [PtCl2(en)2] 2+
Explanation
Solution
Cis – [Pt Cl2(en)2] 2+ has no any element of symmetry so it is optically active