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Question

Mathematics Question on Relations and Functions

Check whether the relation R in R defined as R = {(a, b): a ≤ b3} is reflexive, symmetric or transitive

Answer

R = {(a, b): a ≤ b3}
It is observed that
∴ R is not reflexive.

Now,
(1, 2) ∈ R (as 1 < 23 = 8)
But,
(2, 1) ∉ R (as 23 > 1)
∴ R is not symmetric.

We have (3, 32\frac {3} {2}), (32\frac {3} {2}, 65\frac {6} {5}) ∈ R as 3<(32\frac {3} {2})3 and 32\frac {3} {2}<(65\frac {6} {5})3
But (3, 65\frac {6} {5}) ∉ R as 3>(65\frac {6} {5})3
∴ R is not transitive.

Hence, R is neither reflexive, nor symmetric, nor transitive.