Question

$CHCl_{3}$and HF lead to the formation of a compound of fluorine of molecular weight 70. The compound is.

• A. Fluoroform
• B. Fluorine monoxide
• C. Fluorine dioxide
• D. Fluromethanol

Answer 1

Answer: (A)

Fluoroform

Answer 2

We know that $CHCl_{3} + HF \rightarrow CHF_{3} + 3HCl$. Thus in this reaction the compound obtained in fluoroform $(CHF_{3})$. As we know molecular weight of $CHF_{3} = 70$.