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Question: Charges are placed on the vértices of a square as shown. Let\(\overset{\rightarrow}{E}\) be the elec...

Charges are placed on the vértices of a square as shown. LetE\overset{\rightarrow}{E} be the electric field and V the potential at the centre. If the charges on A and B are interchanged with those on D and C respectively, then –

A

E\overset{\rightarrow}{E} remains unchanged, V changes

B

Both E\overset{\rightarrow}{E} and V changes

C

E\overset{\rightarrow}{E}and V remains unchanged

D

E\overset{\rightarrow}{E}changes, V remains unchanged

Answer

E\overset{\rightarrow}{E}changes, V remains unchanged

Explanation

Solution

Ex = –= –(20x24)\left( \frac { 20 } { x ^ { 2 } - 4 } \right)=

Ex ==40×4144\frac { 40 \times 4 } { 144 }=109\frac { 10 } { 9 } in + x direction.