Question
Question: Charges are placed on the vértices of a square as shown. Let\(\overset{\rightarrow}{E}\) be the elec...
Charges are placed on the vértices of a square as shown. LetE→ be the electric field and V the potential at the centre. If the charges on A and B are interchanged with those on D and C respectively, then –
A
E→ remains unchanged, V changes
B
Both E→ and V changes
C
E→and V remains unchanged
D
E→changes, V remains unchanged
Answer
E→changes, V remains unchanged
Explanation
Solution
Ex = –= –
(x2−420)
=
Ex ==14440×4=910 in + x direction.