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Question

Physics Question on electrostatic potential and capacitance

Charges 5μC5 \mu C and 10μC10 \mu C are placed 1 m apart. Work done to bring these charges at a distance 0.5 m from each other is (k=9×109SI)(k = 9\times 10^9 SI)

A

9×104J9\times10^4 J

B

18×104J18\times10^4 J

C

45×10−2J45\times10^{-2} J

D

9×10−1J9\times10^{-1} J

Answer

9×10−1J9\times10^{-1} J

Explanation

Solution

Given, q1=5mC,q2=10mCq _{1}=5 mC , q _{2}=10 mC, and r=0.5mr =0.5 m
Work done W=14πε0q1q2rW =\frac{1}{4 \pi \varepsilon_{0}} \frac{ q _{1} q _{2}}{ r }
=9×109×5×10−6×10×10−60.5=9 \times 10^{9} \times \frac{5 \times 10^{-6} \times 10 \times 10^{-6}}{0.5}
=9×10−1J =9 \times 10^{-1} J