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Question

Physics Question on Current electricity

Charge passing through a conductor of cross-section area A=0.3m2A=0.3 \,m ^{2} is given by q=3t2+5t+2q=3 t^{2}+5 t+2 in coulomb, where tt is in second. What is the value of drift velocity at t=2s?t=2 s ? (Given, n=2×1025/m3)\left.n=2 \times 10^{25} / \,m ^{3}\right)

A

0.77×105m/s0.77 \times 10^{-5} \,m/s

B

1.77×105m/s1.77 \times 10^{-5}\, m/s

C

2.08×105m/s2.08 \times 10^{-5}\, m/s

D

0.57×105m/s0.57 \times 10^{-5} \,m/s

Answer

1.77×105m/s1.77 \times 10^{-5}\, m/s

Explanation

Solution

The correct option is(B): =1.77×105m/s= 1.77\times 10^{-5} \,m/s.

Given :A=0.3m2: A = 0.3 \,m^{2}
n=2×1025/m3n = 2 \times10^{25}/m^{3}
q=3t2+5t+2q =3t^{2} + 5t +2
i=dqdt=6t+5=17i= \frac{dq}{dt} = 6t +5 = 17
i=neAvdi=n e A v_{d}
Drift velocity, vd=ineAv_{d} = \frac{i}{neA}
=172×1025×1.6×1019×0.3= \frac{17}{ 2\times 10^{25} \times 1.6\times 10^{-19}\times 0.3 }
=170.96×106= \frac{17}{0.96\times 10^{6}}
=1.77×105m/s= 1.77\times 10^{-5} \,m/s