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Question: Change in angular momentum when an electron makes a transition corresponding to the 3rd line of the ...

Change in angular momentum when an electron makes a transition corresponding to the 3rd line of the Balmer series in Li2+ ion is

A

h2π\frac{h}{2\pi}

B

2h2π\frac{2h}{2\pi}

C

3h2π\frac{3h}{2\pi}

D

4h2π\frac{4h}{2\pi}

Answer

3h2π\frac{3h}{2\pi}

Explanation

Solution

Change is angular momentum =Δnh2π=(5−2)h2π=3h2π= \frac{\Delta nh}{2\pi} = (5 - 2)\frac{h}{2\pi} = \frac{3h}{2\pi}