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Question: \[(CH_{3})_{3}C - CH_{2}OH\underset{170ºC}{\overset{\quad Conc.H_{2}SO_{4}\quad}{\rightarrow}}X\] I...

(CH3)3C−CH2OH→Conc.H2SO4170ºCX(CH_{3})_{3}C - CH_{2}OH\underset{170ºC}{\overset{\quad Conc.H_{2}SO_{4}\quad}{\rightarrow}}X

In the reaction X is

A

(CH3)2==CHCH3(CH_{3})_{2} = = CHCH_{3}

B

CH3≡CHCH_{3} \equiv CH

C

(CH3)2CHCH2CH3(CH_{3})_{2}CHCH_{2}CH_{3}

D

Answer

(CH3)2==CHCH3(CH_{3})_{2} = = CHCH_{3}

Explanation

Solution

(CH3)3C−CH2OH→Conc.H2SO4170º(CH3)2=CHCH3(CH_{3})_{3}C - CH_{2}OH\underset{170º}{\overset{\quad Conc.H_{2}SO_{4}\quad}{\rightarrow}}(CH_{3})_{2} = CHCH_{3}