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Question: \[CH_{3} - \underset{\underset{Br}{|}}{C}H - CH_{3}\overset{\quad alc.KOH\quad}{\rightarrow}X\unders...

CH3−C∣BrH−CH3→alc.KOHX→HBrPeroxideY→NaIAcetoneZCH_{3} - \underset{\underset{Br}{|}}{C}H - CH_{3}\overset{\quad alc.KOH\quad}{\rightarrow}X\underset{Peroxide}{\overset{\quad HBr\quad}{\rightarrow}}Y\underset{Acetone}{\overset{\quad NaI\quad}{\rightarrow}}Z

In the given reaction what will be the final product.

A

CH3CH2CH2ICH_{3}CH_{2}CH_{2}I

B

CH3CHICH2ICH_{3}CHICH_{2}I

C

CH3CH2CH2CH2CH3CH_{3}CH_{2}CH_{2}CH_{2}CH_{3}

D

CH3CH2CHI2CH_{3}CH_{2}CHI_{2}

Answer

CH3CH2CH2ICH_{3}CH_{2}CH_{2}I

Explanation

Solution

CH3−C∣BrH−CH3→alc.KOHCH3−CH(X)=CH2→HBrperoxideCH_{3} - \underset{\underset{Br}{|}}{C}H - CH_{3}\overset{\quad alc.KOH\quad}{\rightarrow}CH_{3} - \underset{(X)}{CH} = CH_{2}\underset{peroxide}{\overset{\quad HBr\quad}{\rightarrow}}

CH3CH2CH2Br(Y)→NaIAcetoneCH3CH2CH2I(Z)\underset{(Y)}{CH_{3}CH_{2}CH_{2}Br}\underset{Acetone}{\overset{\quad NaI\quad}{\rightarrow}}\underset{(Z)}{CH_{3}CH_{2}CH_{2}I}