Question

CH3MgCl+SnCl4

Answer 1

Tetramethyltin (($\text{CH}_3)_4\text{Sn}$)

Answer 2

The reaction between methylmagnesium chloride ($\text{CH}_3\text{MgCl}$), a Grignard reagent, and tin(IV) chloride ($\text{SnCl}_4$) is an alkylation reaction. The methyl group from the Grignard reagent acts as a nucleophile, attacking the electrophilic tin center in $\text{SnCl}_4$. All four chlorine atoms on the tin can be replaced by methyl groups.

The overall balanced chemical equation for the reaction is:

$4 \text{ CH}_3\text{MgCl} + \text{SnCl}_4 \rightarrow (\text{CH}_3)_4\text{Sn} + 4 \text{ MgCl}_2$

The main product formed is tetramethyltin, $(\text{CH}_3)_4\text{Sn}$. Magnesium chloride ($\text{MgCl}_2$) is formed as a byproduct.

Explanation:

Methylmagnesium chloride provides methyl anions ($\text{CH}_3^-$ equivalents) which are strong nucleophiles. Tin(IV) chloride has an electrophilic tin atom. The methyl groups replace the chlorine atoms on tin in a stepwise manner, ultimately leading to the formation of tetramethyltin when sufficient Grignard reagent is present.