Question

CH3CH2-Br $\overrightarrow{Acetone}^{NaI}$ CH3-CH2-I+NaBr
Which of the following statement is correct ?

• A. Acetic acid solvent can take in above reaction.
• B. NaI is soluble in acetone but NaBr is precipitate in acetone
• C. NaI is precipitated in acetone but NaBr is soluble in acetone
• D. When acetone is taken in solvent transition state is highly polar

Answer 1

Answer: (B)

NaI is soluble in acetone but NaBr is precipitate in acetone

Answer 2

The correct answer is B
NaI is soluble in the acetone but the NaBr is precipitate in the acetone