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Question

Chemistry Question on Aldehydes, Ketones and Carboxylic Acids

CH3COOH>[LiAlH4]A+CH3COOH>[H3O+]B+H2O CH_3COOH {->[LiAlH_4]} A + CH_3COOH {->[H_3O^+]}B + H_2O In the above reactions A and B respectively are

A

CH3COOC2H5,C2H5PHC{{H}_{3}}COO{{C}_{2}}{{H}_{5}},{{C}_{2}}{{H}_{5}}PH

B

CH3CHO,C2H5OHC{{H}_{3}}CHO,{{C}_{2}}{{H}_{5}}OH

C

C2H5OH,CH3CHO{{C}_{2}}{{H}_{5}}OH,C{{H}_{3}}CHO

D

C2H5OH,CH3COOC2H5{{C}_{2}}{{H}_{5}}OH,C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}

Answer

C2H5OH,CH3COOC2H5{{C}_{2}}{{H}_{5}}OH,C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}

Explanation

Solution

CH3COOH+4H>[LiAlH4]CH3CH2OH(A)+H2OCH_3COOH + 4H {->[LiAlH_4]}\underset{(A)}{CH_3CH_2OH} + H_2O CH3CH2OH(A)+CH3COOH>[H3O+]CH3COOC2H5(B)+H2O\underset{(A)}{CH_3CH_2OH} + CH_3COOH {->[H_3O^+]} \underset{(B)}{CH_3COOC_2H_5} + H_2O