Question

${CH_3CH = CHCHO}$ is oxidised to ${CH_3CH = CHCOOH}$ using

• A. Alkaline $\ce{KMnO_4}$
• B. Selenium dioxide
• C. Ammonical $\ce{AgNO_3}$
• D. All

Answer 1

Answer: (C)

Ammonical $\ce{AgNO_3}$

Answer 2

Weak oxidising agent, Tollen?? reagent (amm. $AgNO_3$).