Question

$CH_3CH_2Br$ undergoes Wurtz reaction. We may expect some of the following product $A : CH_3CH_2CH_2CH_3$ $B : CH_2 = CH_2$ $C : CH_3 ? CH_3$ Select correct product.

• A. Only A
• B. A and B
• C. A, B and C
• D. A and C

Answer 1

Answer: (C)

A, B and C

Answer 2

$C_{2}H_{5}Br + Na^{?} \to CH_{3} CH_{2}^{?} + NaBr$
Intermediate free radical $CH_{3} CH_{2}^{?}$ combines to form $CH_{3}CH_{2} - CH_{2}CH_{3}$ (as amain product) and also $CH_{2} == CH_{2}$ and $C H_{3}CH_{3}$ by disproportion