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Chemistry Question on Hydrocarbons

CH3−CH2−CH=CH2→′X′CH3CH2−CH2−CH2OHCH_3-CH_2-CH=CH_2 \xrightarrow{'X'} CH_3CH_2-CH_2-CH_2OH
What is suitable reagent XX is?

A

H2∣PtH_2|Pt

B

B2H6∣THF,H2O2∣OH−B_2H_6|THF, H_2O_2|OH^-

C

Br2∣HClBr_2|HCl

D

HBr∣H2O2HBr|H_2O_2

Answer

B2H6∣THF,H2O2∣OH−B_2H_6|THF, H_2O_2|OH^-

Explanation

Solution

The correct option is (B): B2H6∣THF,H2O2∣OH−B_2H_6|THF, H_2O_2|OH^-.