Question

Certain perfect gas is found to obeyPV^3/2 = constant during adiabatic process. If such a gas at initial temperature T is adiabatically compressed to half the initial volume, its final temperature will be –

• A. $\sqrt{2}T$
• B. 2T
• C. $2\sqrt{2}T$
• D. 4T

Answer 1

Answer: (A)

$\sqrt{2}T$

Answer 2

PV^3/2 = const. Q P = $\frac{nRT}{V}$

T.V^{3/2 – 1} = const. Ž TV^1/2 = const.