Question
Question: In each situation of column-I, a system involving two bodies is given. All strings and pulleys are l...
In each situation of column-I, a system involving two bodies is given. All strings and pulleys are light and friction is absent everywhere. Initially each body of every system is at rest. Consider the system in all situation of column I from rest till any collision occurs. Then match the statements in column-I with the corresponding results in column-11
Column-I | Column-11 |
---|---|
(A) The block plus wedge system is placed over smooth horizontal surface. After the system is released from rest, the centre of mass of system. | (p) Shifts towards right |
(B) The string connecting both the blocks of mass m is horizontal. Left block is placed over smooth horizontal table as shown. After the two block system is released from rest, the centre of mass of system | (q) Shifts downwards |
(C) The block and monkey have same mass. The monkey starts climbing up the rope. After the monkey starts climbing up, the centre of mass of monkey + block system. | (r) Shifts upwards |
(D) Both block of mass m are initially at rest. The left block is given initial velocily u downwards. Then, the centre of mass of two block system afterwards. | (s) Does not shift (t) shifts towards left |

Answer
A-q, B-q, C-s, D-s
Explanation
Solution
The final answer is A−q,B−q,C−s,D−s.