Question

$\begin{vmatrix} 3-x & 3+x & 3+x \\ 3+x & 3-x & 3+x \\ 3+x & 3+x & 3-x \end{vmatrix}$ If = 0, then the values of x are:

• A. 0, -3
• B. 0, 3
• C. 0, 5
• D. 0,-9

Answer 1

Answer: (D)

0, -9

Answer 2

We are given the determinant

$D = \begin{vmatrix} 3-x & 3+x & 3+x \\ 3+x & 3-x & 3+x \\ 3+x & 3+x & 3-x \end{vmatrix}$

The determinant is $4x^2(x+9)$.

Set $4x^2(x+9) = 0$.

The solutions are:

$x = 0$ or $x = -9$.

Thus, the values of $x$ are $0$ and $-9$.