Question

Case-1

current flowing in steady state find induced e, i in ring?

Answer 1

Induced EMF (e) = 0 Induced Current (i) = 0

Answer 2

In a steady state, the current in the straight wire is constant. A constant current produces a constant magnetic field, which in turn results in a constant magnetic flux through the circular ring. According to Faraday's Law of Electromagnetic Induction ($e = -\frac{d\Phi_B}{dt}$), an induced EMF (e) is generated only when there is a change in magnetic flux. Since the magnetic flux is constant (rate of change is zero), the induced EMF is zero. Consequently, the induced current (i) in the ring is also zero ($i = e/R$).