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Question

Question: Cards with numbers \[2\] to \[101\] are placed in a box. A card is selected at random from the box. ...

Cards with numbers 22 to 101101 are placed in a box. A card is selected at random from the box. Find the probability that the selected card has a number which is a perfect square.
A) 11100\dfrac{{11}}{{100}}
B) 110\dfrac{1}{{10}}
C) 7100\dfrac{7}{{100}}
D) 9100\dfrac{9}{{100}}

Explanation

Solution

We will start with finding favourable outcomes of perfect squares and we are already given total outcomes, so after putting the values in the probability formula we will get our required answer.

Complete step by step answer:
We have been given a few cards numbered 22 to 101101 are placed in a box. So, we have in total 100100 cards.
Now a card is selected at random, we need to find the probability that the card selected has a number which is a perfect square.

So, perfect squares between 22 and 101$$$$ = {\text{ }}\left\\{ {4,9,16,25,36,49,64,81,100} \right\\}
Number of favourable outcomes of perfect squares = 9 = {\text{ }}9
And, the total outcomes of cards = 100 = {\text{ }}100
We know that, Probability == favourable outcomestotal outcomes\dfrac{{favourable{\text{ }}outcomes}}{{total{\text{ }}outcomes}}
So, probability of getting a number which is a perfect square =9100 = \dfrac{9}{{100}}

Hence, option (D), 9100\dfrac{9}{{100}} is correct.

Note: Students should carefully obtain perfect squares from 22 to 101.101. As this is the first step and will be our favourable outcomes of perfect squares, so this should be correct, otherwise the answer can get wrong.