Question

Carbon is in the lowest oxidation state in.

• A. $CH_{4}$
• B. $CCl_{4}$
• C. $CF_{4}$
• D. $CO_{2}$

Answer 1

Answer: (A)

$CH_{4}$

Answer 2

: Oxidation number of carbon in the given compounds:

In $\overset{x + 1}{CH_{4}} = x + 4( + 1) = 0 \Rightarrow x = - 4$

In

In $\overset{x - 1}{CF_{4}} = x + 4( - 1) = 0 \Rightarrow x = + 4$

In