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Question: Can someone help me with this? Concentrated \( HN{O_3} \) has a specific gravity of \( 1.42 \) . It ...

Can someone help me with this? Concentrated HNO3HN{O_3} has a specific gravity of 1.421.42 . It contains 69%w/w69\% w/w (weight by weight) of HNO3HN{O_3} . calculate the molarity and molality of the solution?

Explanation

Solution

From specific gravity, the density will be calculated. Using the density and volume of solution as one litre, gives the mass of solution. From the given weight by weight of HNO3HN{O_3} mass of nitric acid can be determined. It helps in determining the moles of HNO3HN{O_3} . Thus, moles of HNO3HN{O_3} and volume of solution given molarity. Later the mass of water in kilograms and moles of HNO3HN{O_3} gives molality.

Complete answer:
Given specific gravity of concentrated HNO3HN{O_3} is 1.421.42
S=ρHNO3ρH2Oat40CS = \dfrac{{{\rho _{HN{O_3}}}}}{{{\rho _{{H_2}O}}at{4^0}C}}
By substituting the given specific gravity and water density at 40C{4^0}C which is 1gml11gm{l^{ - 1}}
The density of nitric acid will be 1.42gml11.42gm{l^{ - 1}}
The mass of solution will be 1.42×1000=1420gm1.42 \times 1000 = 1420gm
Given 69%w/w69\% w/w (weight by weight) of HNO3HN{O_3} it means 100gm100gm of solution consists of 69gmHNO369gmHN{O_3}
Thus, the solution consists of 1420×69100=979.8gHNO31420 \times \dfrac{{69}}{{100}} = 979.8gHN{O_3}
Nitric acid has molar mass of 63.01gmol163.01gmo{l^{ - 1}}
Thus, moles of HNO3HN{O_3} will be 979.863.01=15.55moles\dfrac{{979.8}}{{63.01}} = 15.55moles
Molarity is the ratio of number of moles of HNO3HN{O_3} which is solute divided by volume of solution in litres
M=15.551=15.6MM = \dfrac{{15.55}}{1} = 15.6M
Molarity of nitric acid is 15.6M15.6M
Mass of solution is 1420gm1420gm
Mass of nitric acid is 979.8g979.8g
Thus, mass of water will be 1420979.8=440.2g1420 - 979.8 = 440.2g
When the mass of water is converted into kilograms from mass,
Molality is the ratio of the moles of concentrated nitric acid to mass of water in kilograms
m=15.55440.2×103=35.3mm = \dfrac{{15.55}}{{440.2 \times {{10}^{ - 3}}}} = 35.3m
The Molarity of nitric acid is 35.3m35.3m .

Note:
While calculating the molarity, the volume of solution must be in litres, if the volume of solution is in millilitres it should be multiplied by 10001000 . While calculating the molality, the mass of the solvent must be in kilograms, if it is in grams, it should be converted into kilograms.