Question
Question: Can someone help me with this? Concentrated \( HN{O_3} \) has a specific gravity of \( 1.42 \) . It ...
Can someone help me with this? Concentrated HNO3 has a specific gravity of 1.42 . It contains 69%w/w (weight by weight) of HNO3 . calculate the molarity and molality of the solution?
Solution
From specific gravity, the density will be calculated. Using the density and volume of solution as one litre, gives the mass of solution. From the given weight by weight of HNO3 mass of nitric acid can be determined. It helps in determining the moles of HNO3 . Thus, moles of HNO3 and volume of solution given molarity. Later the mass of water in kilograms and moles of HNO3 gives molality.
Complete answer:
Given specific gravity of concentrated HNO3 is 1.42
S=ρH2Oat40CρHNO3
By substituting the given specific gravity and water density at 40C which is 1gml−1
The density of nitric acid will be 1.42gml−1
The mass of solution will be 1.42×1000=1420gm
Given 69%w/w (weight by weight) of HNO3 it means 100gm of solution consists of 69gmHNO3
Thus, the solution consists of 1420×10069=979.8gHNO3
Nitric acid has molar mass of 63.01gmol−1
Thus, moles of HNO3 will be 63.01979.8=15.55moles
Molarity is the ratio of number of moles of HNO3 which is solute divided by volume of solution in litres
M=115.55=15.6M
Molarity of nitric acid is 15.6M
Mass of solution is 1420gm
Mass of nitric acid is 979.8g
Thus, mass of water will be 1420−979.8=440.2g
When the mass of water is converted into kilograms from mass,
Molality is the ratio of the moles of concentrated nitric acid to mass of water in kilograms
m=440.2×10−315.55=35.3m
The Molarity of nitric acid is 35.3m .
Note:
While calculating the molarity, the volume of solution must be in litres, if the volume of solution is in millilitres it should be multiplied by 1000 . While calculating the molality, the mass of the solvent must be in kilograms, if it is in grams, it should be converted into kilograms.