Question

Calculate the weight of dilute sulphuric acid solution $\left( {sp.gr = 1} \right)$which was electrolyzed to give ${H_2}$AT $300K$ and 1atm to fill a balloon of capacity $680L$.

Answer 1

We must have to know that the sulphuric acid is a chemical element having the formula, ${H_2}S{O_4}$. And the composition of sulphuric acid is sulphur, hydrogen and oxygen. It is a viscous liquid which is odorless and colorless in nature. And by the electrolysis of sulphuric acid, there is a formation of hydrogen. We also need to know that sulphuric acid is mainly used for the preparation of fertilizers and for the manufacturing of chemicals like sulphate salts, nitric acid, hydrochloric acid etc.

Complete answer:
According to the question, the temperature and pressure is equal to$300K$and 1 atm respectively.
During the electrolysis reaction of sulphuric acid, there is a formation of hydrogen as well as oxygen. The hydrogen is generated at the cathode and oxygen is generated at anode. The reaction formation of hydrogen is,
$2{H^ + } + 2{e^ - } \to {H_2}$
And one mole of sulphuric acid is producing two moles of hydrogen.
Therefore, the weight of sulphuric acid$= \dfrac{{0.98}}{2} = 0.49g$

Note:
We must have to know that the chemical decomposition of compounds by using electric current is known as electrolysis. And the current passes through a liquid. During the electrolysis of sulphuric acid, there is a formation of hydrogen and it is generated at cathode and the oxygen is generated at anode position. And dilute sulphuric acid is used for the preparation which contains water also. Therefore, the mixture contains hydrogen as well as hydroxide ions which come from water. And hydrogen ions and sulphate ions come from sulphuric acid.