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Chemistry Question on Structure of atom

Calculate the wavelength (in nanometer) associated with a proton moving at 1.0×103ms−11.0 \times 10^3ms^{-1} (Mass of proton =1.67×10−27 kg= 1.67 \times 10^{-27}\, kg and h=6.63×10−34 Jsh = 6.63 \times 10^{-34}\, Js ) :

A

0.032 nm0.032\, nm

B

0.40 nm0.40\, nm

C

2.5 nm2.5\, nm

D

14.0 nm14.0\, nm

Answer

0.40 nm0.40\, nm

Explanation

Solution

λ=hmv=6.63×10−341.67×10−27×103=0.40 nm\lambda=\frac{h}{mv}=\frac{6.63\times10^{-34}}{1.67\times10^{-27}\times10^{3}}=0.40\,nm