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Question

Chemistry Question on Developments Leading to the Bohr’s Model of Atom

Calculate the wavelength, frequency and wave number of a light wave whose period is 2.0×1010 s2.0×10^{–10}\ s.

Answer

Frequency of light:
ν=1Periodν = \frac {1}{\text P{eriod}}

ν=12.0×1010 sν = \frac {1}{2.0×10^{-10} \ s}
ν=5.0×109 s1ν = 5.0×10^9 \ s^{-1}
Wavelength of light λ=cvλ = \frac cv
Where,
c = velocity of light in vacuum = 3×108 m/s3×10^8\ m/s
Substituting the value in the given expression of λ:
λ=3×1085.0×109λ = \frac {3×10^8}{5.0×10^9}
λ=6.0×102 mλ = 6.0×10^{-2}\ m
Wave number of light:
νˉ=1λ\bar ν = \frac 1λ
νˉ=16.0×102\bar ν=\frac {1}{6.0×10^{-2}}
νˉ=1.66×101 m1\bar ν= 1.66 × 10^1\ m^{-1}
νˉ=16.66 m1\bar ν= 16.66 \ m^{-1}