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Chemistry Question on Structure of atom

Calculate the wavelength associated with an electron moving with a velocity of 106m/s10^{6} m / s (mass of e−=9.1×10−31kg, h=6.6×10−34kg m2s−1)e^{-}=9.1 \times 10^{-31} kg,\, \left. h=6.6 \times 10^{-34} kg\, m ^{2} s ^{-1}\right)

A

6.2×10−8 m6.2\times 10^{-8}\,m

B

7.25×10−8 m7.25\times 10^{-8}\,m

C

6.25 ? 6.25\,?

D

None of the above

Answer

None of the above

Explanation

Solution

According to de-Broglie equation
λ=hmv\lambda=\frac{h}{m v}
=6.6×10−34kgm2s−19.1×10−31kg×106ms−1=\frac{6.6 \times 10^{-34} kg m ^{2} s ^{-1}}{9.1 \times 10^{-31} kg \times 10^{6} ms ^{-1}}
=0.725×10−9m=0.725 \times 10^{-9} m
=7.25×10−10m=7.25 \times 10^{-10} m