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Question: Calculate the volume of oxygen at NTP that would be required to convert L of carbon monoxide to carb...

Calculate the volume of oxygen at NTP that would be required to convert L of carbon monoxide to carbon dioxide.
A.5.25.2L
B.2.52.5L
C.3.423.42L
D.None of these

Explanation

Solution

The volume of 11 mole of any gas is called its molar volume and is equal to 22.4  22.4\; L at standard temperature and pressure (according to the ideal gas law) Molar volume allows conversions to be made between moles and volume of gases at STP.

Complete step by step answer:
The chemical reaction for the equation in the question is :
CO+12O2CO2CO + \dfrac{1}{2}{O_2} \to C{O_2}
Final moles of 55 liters of COCO :
If 22.4  22.4\; liters of COCO is 11 mole
Then 55 liters of CO=1×522.4=0.223  molesCO = 1 \times \dfrac{5}{{22.4}} = 0.223\;moles
The equation for the reaction of the oxidation of COCO is
The mole ratio between COCO and O2{O_2}​ in the equation is 2:12:1
The mole of 55 litres COCO is 0.2330.233 moles
Since2:12:1 mole ratio is , as seen in the reaction above
We need 0.2332\dfrac{{0.233}}{2} moles of oxygen
0.112 mol=0.112 = 0.112es of oxygen to react with COCO
Then 0.112  moles  =0.112×22.4/1=2.5  litre0.112\;moles\; = 0.112 \times 22.4/1 = 2.5\;litre.
So the correct option is B)

Note: Avogadro’s hypothesis states that equal volumes of all gases at the identical temperature and pressure contain the identical number of particles. A graph of the effect of temperature on the degree of a gas at constant pressure depicts that the amount of a gas is directly proportional to the amount of moles of that gas. this can be called because the Avogadro’s law.
The critical chemical difference is that CO2 contains one atom of carbon and two atoms of oxygen, whilst CO has one carbon and one oxygen atom. carbonic acid gas is non-flammable, whilst CO isn't. greenhouse emission naturally occurs within the atmosphere . However, CO doesn't occur naturally within the atmosphere and might cause health problems even in low concentrations. The density of both gases is additionally different in values.