Question
Question: Calculate the volume in litres of \[49.8{\text{ }}gram\] of \[HCl\] gas at STP (molar mass of \[HCl\...
Calculate the volume in litres of 49.8 gram of HCl gas at STP (molar mass of HCl =1 atmosphere,i.e.,760 mm Hg.
Solution
At standard Temperature and Pressure (STP) the volume occupied by one mole of any gas is 22.4 litres This volume is called the standard molar volume. It is said that 22.4 litres of any gas at STP weighs equal to its molecular mass in grams.
Complete Step by step answer: At standard temperature (STP) is an elementary concept. In the STP system, both pressure and temperature are in their typical form. Temperature of this system is considered as 273 Kelvin or 0oC and Standard pressure is 1 atmosphere,i.e.,760 mm Hg. Then experimentally, one mole of any gas occupies a volume of 22.4 litres at 273 Kelvin and 1 atmosphere. The equation can be expressed
(1 mole of gas at STP=22.4 litres of gas.)
Now we can calculate the volume of 22.4 litres of the gas at S.T.P from the given weight.
Given, According to the question, the weight of HCl gas at STP = 49.8 gram
Molar mass of HCl= (36.5g−mol−1)
Now 22.4 litres of any gas at S.T.P. weighs equal to its molecular mass in grams.
∴36.5goccupies=22.4 litres of volume
∴ 49.8 gram of HCloccupies =36.549.8×22.4 =30.56litres.
So the volume in litres of 49.8 gram of HCl gas at STP = =30.56litres.
Note: STP conditions are often used for engineering calculations for a gas flow or gas volume is involved. When gas volume is considered at a fixed reference temperature & pressure, its 'standard volume' is directly proportional to the molar quantity. Gas density measured at STP conditions is also a good measure of the composition of that gas, another common form of STP called standard ambient temperature and pressure or S.A.T.P. is used.