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Question: Calculate the value of the unknown potential V for the given potentiometer circuit. The total length...

Calculate the value of the unknown potential V for the given potentiometer circuit. The total length (400 cm) of the potentiometer wire has a resistance of 10Ω and the balance point is obtained at a length of 240 cm

A. 0.06 V
B. 0.6 V
C. 6 V
D. None of these

Explanation

Solution

In this question we have been asked to calculate the unknown potential V for the given potentiometer circuit. Therefore, to solve this question, we shall first discuss what is a potentiometer briefly. We know that for a balanced point in a potentiometer, the ratio of two emf of a battery is equal to the ratio of lengths. Therefore, we shall use this concept to calculate the unknown potential or emf of the battery.
Formula used: V=IRV=IR

Complete step by step solution:
We know that potentiometer is the electrical device used to compare the emfs of two cells. It is also used to calculate the internal resistance of a cell or measure its potential difference. The balance point is obtained in a potentiometer by connecting one of the batteries between the galvanometer. The jockey is moved until the galvanometer shows no deflection. The length of wire is taken as l1{{l}_{1}}.
The emf of battery is then given as,
E1=l1LV{{E}_{1}}=\dfrac{{{l}_{1}}}{L}V …………….. (2)
Similarly, when second battery is connected, the emf is given by,
E2=l2LV{{E}_{2}}=\dfrac{{{l}_{2}}}{L}V ………… (1)
Therefore, from (1) and (2) we get,
E1E2=l1l2\dfrac{{{E}_{1}}}{{{E}_{2}}}=\dfrac{{{l}_{1}}}{{{l}_{2}}}.
Now, from the diagram, we know that the resistance given is 290 ohms. This resistor is in series with the wire having 10 ohms resistance. Therefore, the total resistance is
R=290+10=300ΩR=290+10=300\Omega
Therefore, using Ohm's law
We get,
V=IRV=IR
Substituting the given values
We get,
3=300×I3=300\times I
Therefore,
I=102AI={{10}^{-2}}A …………… (3)
Now, it is also given that the resistance of 400 cm of wire is 10 ohms.
Therefore, resistance of 240 cm length of wire will be,
R=240×(10400)R=240\times \left( \dfrac{10}{400} \right)
R=6ΩR=6\Omega …………………. (4)
Now, substituting (3) and (4) in Ohm's law
We get,
V0=102×6{{V}_{0}}={{10}^{-2}}\times 6
Therefore,
V0=0.06V{{V}_{0}}=0.06V
Therefore, the correct answer is option A.

Note: A potentiometer is an electrical device with three-terminal resistors with sliding contact that forms an adjustable voltage divider. The potentiometer acts as the rheostat when only two terminals are used. It is a measuring device used to measure the electric potential of the circuit. Potentiometers are commonly used to control electrical devices such as audio control.