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Question: Calculate the value of resistor \(X\). ![](https://www.vedantu.com/question-sets/6832528e-da92-468...

Calculate the value of resistor XX.

Explanation

Solution

In order to solve this question you have to know the concept of Ohm's law which states that the potential difference across the two points is directly proportional to the current through a conductor between that two points. Also, in order to solve this you have to know the equivalent resistance of the resistors connected in series or parallel.

Formula used:
The voltage difference across two points is given by,

V=IRV = IR

Where, VV is the voltage across two points
II is the current through the conductor
RR is the resistance

Complete step by step solution:
Here, in this question we have given the voltage across the battery connected, which is given by,

V=8VV = 8V

And also the current flowing in the circuit is given by,

I=0.5AI = 0.5A

In the circuit we have given four resistances which are connected in series and parallel, we have to find the equivalent resistance of all the resistors connected
Firstly, find the equivalent resistance of the three resistors connected in parallel
We know that,

1Req=1R1+1R2+1R3\dfrac{1}{{{{R'}_{eq}}}} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}} + \dfrac{1}{{{R_3}}}

On putting the values of all three resistors, we have

1Req=14+112+16 \Rightarrow \dfrac{1}{{{{R'}_{eq}}}} = \dfrac{1}{4} + \dfrac{1}{{12}} + \dfrac{1}{6}

On further solving

Req=2Ω\Rightarrow {R'_{eq}} = 2\Omega

Now, this 2Ω2\Omega is in series with 4Ω4\Omega and XX.
So, the total equivalent resistance is given by,

Req=4Ω+2Ω+X{R_{eq}} = 4\Omega + 2\Omega + X
Req=(6+X)Ω\Rightarrow {R_{eq}} = (6 + X)\Omega

Now, applying the ohm’s law

According to ohm’s law, we know that the voltage difference across two points is given by,

V=IRV = IR

Where, VV is the voltage across two points
II is the current through the conductor
RR is the resistance

On putting all the values we have,

8=0.5×(6+X) \Rightarrow 8 = 0.5 \times \left( {6 + X} \right)

From the above equation, we have to find the value of XX

8=3+0.5X \Rightarrow 8 = 3 + 0.5X

On further solving, we have

X=10Ω\Rightarrow X = 10\Omega

Therefore, the value of resistor XX is 10Ω10\Omega .

Note: The equivalent resistance of any circuit is the ratio of the potential difference across the circuit to the total current flowing through the battery or more appropriately the circuit. If the circuit has many resistors then their individual resistances are the ratios of the individual potential differences across them to the individual currents flowing through them.