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Question: Calculate the total entropy change for the transition at 368K for 1mol of sulphur from the monoclini...

Calculate the total entropy change for the transition at 368K for 1mol of sulphur from the monoclinic to the rhombic solid state, is ΔH=401.7Jmol1\Delta H=-401.7Jmo{{l}^{-1}} for the transition. Assume the surroundings to be an ice-water both at 0C0{}^\circ C.
(A) 1.09JK1-1.09J{{K}^{-1}}
(B) 0.5JK1-0.5J{{K}^{-1}}
(C) 0.385JK1-0.385J{{K}^{-1}}
(D) None of these

Explanation

Solution

Think about the property of entropy of a thermodynamic process. We need to calculate the total entropy change for transition of sulphur from monoclinic form to rhombic form. The total entropy change is given as, ΔStotal=ΔSsystem+ΔSsurroundings\Delta {{S}_{total}}=\Delta {{S}_{system}}+\Delta {{S}_{surroundings}}. Just substitute the values and find out the answer.

Complete answer:
- According to the second law of thermodynamics, the total entropy change of the system and its surroundings increases in a spontaneous process. Mathematically, for a spontaneous process, ΔStotal=ΔSsystem+ΔSsurroundings\Delta {{S}_{total}}=\Delta {{S}_{system}}+\Delta {{S}_{surroundings}}
- Therefore, the total entropy change is the sum of entropy change of system and that of surroundings.
- The entropy change of a system is defined as the change in heat enthalpy per unit temperature in kelvin.
ΔS=ΔHT\Delta S=\dfrac{\Delta H}{T}
- The entropy change for a surrounding is given as,
ΔSsurroundings=ΔHT\Delta {{S}_{surroundings}}=-\dfrac{\Delta H}{T}
- For the transition of sulphur from monoclinic form to rhombic form, ΔH=401.7Jmol1\Delta H=-401.7Jmo{{l}^{-1}}.
- The temperature of the monoclinic system, T1{{T}_{1}} is 368K and of rhombic form, T2{{T}_{2}} is 273K.
- Therefore, the total change in entropy is given as,

& \Delta {{S}_{total}}=\Delta {{S}_{system}}+\Delta {{S}_{surroundings}} \\\ & =\dfrac{\Delta H}{{{T}_{2}}}-\dfrac{\Delta H}{{{T}_{1}}} \\\ & =\dfrac{-401.7}{273}-\dfrac{-401.7}{368} \\\ & =-1.471+1.092 \\\ & \Delta {{S}_{total}}=-0.38J{{K}^{-1}} \end{aligned}$$ \- Therefore, the total entropy change is -0.38J/K. **Therefore, the correct answer is option (C).** **Note:** Remember entropy is a thermodynamic property which gives an idea about the degree of randomness in a system. Entropy depends on change in heat enthalpy and temperature. For spontaneous processes, total entropy change is greater than zero. At equilibrium, total entropy change is zero. For non-spontaneous processes, total entropy change is less than zero.