Question

Calculate the temperature on Celsius scale whose value is half the absolute scale reading?

Answer 1

As we know the formula of $A = 273 + C$ where $A$ is temperature in kelvin and $C$is temperature in degree Celsius and we are also given in the question that $C = \dfrac{A}{2}$ and substitute it in the formula to get answer.

Complete step-by-step solution:

As in the question we are given with Celsius scale and absolute reading scale that is $C$and $A$,

And in the question we are also given that Celsius scale is half of absolute reading that is $C = \dfrac{A}{2}$

And we know the formula of relation between Celsius and absolute scale is $A = 273 + C$

Now substitute the value of $C$as given above in the question

$A = 273 + \dfrac{A}{2}$

$\dfrac{A}{2} = 273$

$A = 546$, now substitute the value calculated in the relation given in the question of Celsius and absolute reading, so we get

$C = \dfrac{A}{2}$

$C = 273$

So, the temperature in Celsius scale will be $273 {^{\circ}}C$

Additional Information:

The thought that there is an at last least temperature was proposed by the conduct of gases at low weights: it was noticed that gases appear to contract uncertainly as temperature diminishes. It created the impression that an "ideal gas" at steady weight would arrive at zero volume at what is presently called without a doubt the zero of temperature. Any genuine gas really gathers to a fluid or a strong at some temperature higher than total zero. In this manner, the ideal gas law is just an estimate to genuine gas conduct. In that capacity, nonetheless, it is incredibly helpful. The idea of outright zero as a restricting temperature has numerous thermodynamic results. For instance, all sub-atomic movement doesn't stop at supreme zero (particles vibrate with what is called zero-point vitality), yet no vitality from sub-atomic movement (that is, heat vitality) is accessible for move to different frameworks, and it is along these lines right to state that the vitality at outright zero is insignificant.

Note: Remember the concept of absolute reading that is $273 + C$ and in the above question as we have calculated the value of $A$ and then by substitution calculated the value of $C$ but you can calculate the velocity of $C$ by substitution value of $C$ in $A$.