Question

Calculate the standard free energy change for the reaction, $2 \mathrm { Ag } + 2 \mathrm { H } ^ { + } \rightarrow \mathrm { H } _ { 2 } + 2 \mathrm { Ag } ^ { + }$ $\mathbf{E}^{\mathbf{0}}$for

$Ag^{+} + e^{-} \rightarrow Ag$is 0.80 V

• A. $+ 154.4kJ$
• B. $+ 308.8kJ$
• C. $- 154.4kJ$
• D. –$\text{308.8kJ}$

Answer 1

Answer: (A)

$+ 154.4kJ$

Answer 2

For the given reaction $E_{cell}^{0} = - 0.80V$

$\Delta G = - nFE_{cell}^{0}$=–2×96500×(–0.80)J=154400J =154.4kJ