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Question: Calculate the shortest and longest wavelength \((\lambda )\) in the Lyman series of Hydrogen atoms. ...

Calculate the shortest and longest wavelength (λ)(\lambda ) in the Lyman series of Hydrogen atoms.
Rydberg's constant = 109,677cm1109,677c{m^{ - 1}}

Explanation

Solution

The atomic structure of hydrogen consists of a large number of spectral lines which are grouped into five series which are Lyman , Balmer , Paschen ,Brackett and Pfund . In the given question we have to find the wavelength in the Lyman series .

Complete step by step answer:
When an electron jumps from higher energy levels (n>1)(n > 1) to n=1 energy level , the group of lines produced are termed as Lyman series .
To calculate the shortest and longest wavelength in Lyman series of Hydrogen atom we will use Rydberg formula which is given by
1λ=R(1n121n22)\dfrac{1}{\lambda } = R(\dfrac{1}{{n_1^2}} - \dfrac{1}{{n_2^2}})
where , λ\lambda = wavelength , R = Rydberg's constant ,
n1{n_1} = the lower energy level to which the electron jumps ( in case of Lyman series n1=1{n_1} = 1 ) n2{n_2} = The higher energy level from which the electron jumps .
Now , first we will calculate the shortest wavelength , For the wavelength to be minimum the energy difference in two states showing transition should be maximum , that is n2={n_2} = \infty .
So on substituting the values in the rydberg's formula we get ,
1λ=109677(11212)\dfrac{1}{\lambda } = 109677(\dfrac{1}{{{1^2}}} - \dfrac{1}{{{\infty ^2}}})
λ=1109677=911.7A\Rightarrow \lambda = \dfrac{1}{{109677}} = 911.7{A^ \circ }
Now to calculate the longest wavelength the energy difference in two states showing transition should be maximum , that is n2=2{n_2} = 2 .
So on substituting the values we get
1λ=109677(112122)\dfrac{1}{\lambda } = 109677(\dfrac{1}{{{1^2}}} - \dfrac{1}{{{2^2}}})
λ=43×109677=1215.69A\Rightarrow \lambda = \dfrac{4}{{3 \times 109677}} = 1215.69{A^ \circ }
Therefore , the shortest and longest wavelengths in Lyman series of hydrogen are 911.7A911.7{A^ \circ } and 1215.69A1215.69{A^ \circ } respectively .

Note:
The line spectrum of hydrogen is explained by Bohr's model . According to Bohr's model , an electron neither emits or absorbs energy as long as it is in the same energy level but it emits or absorbs energy when it jumps from one level to another .