Question
Question: Calculate the shortest and longest wavelength \((\lambda )\) in the Lyman series of Hydrogen atoms. ...
Calculate the shortest and longest wavelength (λ) in the Lyman series of Hydrogen atoms.
Rydberg's constant = 109,677cm−1
Solution
The atomic structure of hydrogen consists of a large number of spectral lines which are grouped into five series which are Lyman , Balmer , Paschen ,Brackett and Pfund . In the given question we have to find the wavelength in the Lyman series .
Complete step by step answer:
When an electron jumps from higher energy levels (n>1) to n=1 energy level , the group of lines produced are termed as Lyman series .
To calculate the shortest and longest wavelength in Lyman series of Hydrogen atom we will use Rydberg formula which is given by
λ1=R(n121−n221)
where , λ = wavelength , R = Rydberg's constant ,
n1 = the lower energy level to which the electron jumps ( in case of Lyman series n1=1 ) n2 = The higher energy level from which the electron jumps .
Now , first we will calculate the shortest wavelength , For the wavelength to be minimum the energy difference in two states showing transition should be maximum , that is n2=∞ .
So on substituting the values in the rydberg's formula we get ,
λ1=109677(121−∞21)
⇒λ=1096771=911.7A∘
Now to calculate the longest wavelength the energy difference in two states showing transition should be maximum , that is n2=2 .
So on substituting the values we get
λ1=109677(121−221)
⇒λ=3×1096774=1215.69A∘
Therefore , the shortest and longest wavelengths in Lyman series of hydrogen are 911.7A∘ and 1215.69A∘ respectively .
Note:
The line spectrum of hydrogen is explained by Bohr's model . According to Bohr's model , an electron neither emits or absorbs energy as long as it is in the same energy level but it emits or absorbs energy when it jumps from one level to another .