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Question

Question: Calculate the resistivity of the material of a wire 1 m long , 0.4 mm in diameter and having a resis...

Calculate the resistivity of the material of a wire 1 m long , 0.4 mm in diameter and having a resistance 2Ω.
A) 300Ωm300\Omega m
B) 2.514×107Ωm2.514\times {{10}^{-7}}\Omega m
C) 2×107Ωm2\times {{10}^{7}}\Omega m
D) 1×1015Ωm1\times {{10}^{-15}}\Omega m

Explanation

Solution

Resistivity also known as specific electrical resistance is defined as the measure of the resistance of a given size of a particular material to electrical conduction.
Electrical resistivity is the electrical resistance per unit length and per unit of cross-sectional area at a specified temperature and is given by-
ρ=RAl\rho =R\dfrac{A}{l} where,
R is the electrical resistance of the material measured in ohms
l is the length of material measured in metres, m
A is the cross-sectional area of the specimen measured in square metres, m2{{m}^{2}}
In the given question, we will first find the area of cross-section and then put all the values in formula to find the resistivity of material.

Complete Step-by-step solution:
As mentioned the known
R=2ΩR=2\Omega
l=1ml=1m
d=0.4mm=0.0004md=0.4mm=0.0004m
First, we will calculate the area of cross-section of material which is given by
A=πd24A=\dfrac{\pi {{d}^{2}}}{4}--------- (1)
Substitute the value of d in equation (1) we get
A=π×(0.0004)24A=\dfrac{\pi \times {{(0.0004)}^{2}}}{4}
A=3.14×0.000000164A=\dfrac{3.14\times 0.00000016}{4}
A=1.256×107m2A=1.256\times {{10}^{-7}}{{m}^{2}}
Now, we need to find the resistivity of the material.
We know, ρ=RAl\rho =R\dfrac{A}{l}------------- (2)
Substituting the values in equation (2) ,we get
ρ=2×1.256×1071\rho =\dfrac{2\times 1.256\times {{10}^{-7}}}{1}
ρ=2.514×107Ωm\rho =2.514\times {{10}^{-7}}\Omega m

**Hence, the resistivity of the material is 2.514×107Ωm2.514\times {{10}^{-7}}\Omega m
Correct Option is B **

Note:
A material's resistivity can also be defined in terms of the magnitude of the electric field through it that gives a certain density of current. An electrical resistivity formula can be designed which is generated by—
ρ=EJ\rho =\dfrac{E}{J} where,
ρ is the resistivity of the material.
E is the magnitude of the electric field.
J is the magnitude of the current density.
The resistivity of perfect conductors is 0. There is no resistance at all in perfect conductors.
Resistivity is limitless for ideal insulators. As a consequence of resistance, there are so many barriers that current does not flow at all.
Resistance tells of the conductor's resistance as a whole, while resistivity tells of a given material's resistance.