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Question: Calculate the\[pH\]of orange juice in which hydronium ion conc. \[\left( {{H_{3}}{O^ + }} \right)\;i...

Calculate thepHpHof orange juice in which hydronium ion conc. (H3O+)  is 2  ×  108  mol/l  .\left( {{H_{3}}{O^ + }} \right)\;is{\text{ }}2\; \times \;{10^{ - 8\;}}mol/l\;.

Explanation

Solution

To calculate the pHpH of a orange juice , we have to used the formula: pHpH=log10[H3O+] - lo{g_{10}}\left[ {{H_3}{O^ + }} \right]. As per equation, the pHpH of a solution is the negative of base 1010logarithm of hydronium ion concentration in a solution. The concentration of hydronium ions in an aqueous solution can provide information about the acidic, basic, or neutral nature of a solution. At room temperature, the pH of neutral water is equal to 77.

Complete step by step answer:
pHpH stands for potential of hydrogen and pHpH scale is a logarithmic scale that is used to measure the acidity or the basicity of a substance. The range of the scale varies from 0 to 140{\text{ }}to{\text{ }}14. Solutions having a value of pHpH ranging  0 to 7\;0{\text{ }}to{\text{ }}7on pHpH scale are known as acidic and for the value of pHpH ranging 7 to 147{\text{ }}to{\text{ }}14on pHpH scale are called basic solutions and the Solutions having the value of pH equal to 77 on pHpH scale are termed as neutral solutions.
When we determine the pHpH value of orange juice, we need to know the concentration of hydronium ions in moles per liter (molarity) of the solution.
To calculate the pHpH of a solution, use the equation pHpH= log10[H3O+] - lo{g_{10}}\left[ {{H_3}{O^ + }} \right]
Given,
Concentration of Hydronium Ion \left( {{H_3}{O^ + }} \right)$$$$ = 2 \times {10^{ - 8}}moles/l
[H3O+]\left[ {{H_3}{O^ + }} \right] =2×108 = 2 \times {10^{ - 8}}
pHpH=log10[H3O+] - lo{g_{10}}\left[ {{H_3}{O^ + }} \right]
pH=log10[2×108]pH = - lo{g_{10}}\left[ {2 \times {{10}^{ - 8}}} \right]
By solving the log
\therefore we know that, log1010=1{\log _{10}}10 = 1 and log2=0.3010log2 = 0.3010
pH=[log10(2)+log10(108)]pH = - \left[ {lo{g_{10}}(2) + {{\log }_{10}}({{10}^{ - 8}})} \right]
pH=[0.30108]pH = - \left[ {0.3010 - 8} \right]
pH=80.3010pH = 8 - 0.3010
pH=7.6990pH = 7.6990
Note: pH  pH\; measurement is used in a wide variety of applications: agriculture, wastewater treatment, industrial processes, environmental monitoring, and in research and development. In our real life pH  pH\; is important because substances such as our stomach acids tend to be at certain pHpH in order to work properly and it must be at certain levels in order for living organisms to survive.