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Chemistry Question on coordination compounds

Calculate the overall complex dissociation equilibrium constant for the [Cu(NH3)4]2+[Cu(NH_3)_4]^{2+} ions, given that stability constant (β\beta) for this complex is 2.1×10132.1 \times 10^{13}.

A

8.27×10−138.27 \times 10^{-13}

B

4.76×10−144.76 \times 10^{-14}

C

2.39×10−72.39 \times 10^{-7}

D

1.83×10141.83 \times 10^{14}

Answer

4.76×10−144.76 \times 10^{-14}

Explanation

Solution

Dissociation constant is the reciprocal of the stability constant (β\beta = 1/K). Overall complex dissociation equilibrium constant, K=1β4K = \frac{1}{\beta_{4}} =12.1×1013=4.76×10−14\quad\quad\quad=\frac{1}{2.1\times10^{13}}=4.76\times10^{-14}