Question

Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol–1 K–1.

Answer 1

From the expression of heat ($q$),
$q = m. c. ∆T$
Where,
$c$ = molar heat capacit m = mass of substance
$∆T$ = change in temperature
Substituting the values in the expression of $q$:
$q = (\frac {60}{27}\ mol)(24\ J mol^{-1}k^{-1})(20\ K)$
$q = 1066.7\ J$
$q = 1.07\ kJ$