Question

Calculate the number of hours of service that can be derived at 1 atm& 300K from an acetylene lamp containing 640 g calcium carbide. Given that the lamp requires 50 L acetylene gas at 1 atm& 300K for one hour. [Take 0.0821 × 300 = 25] –

• A. 5 hrs
• B. 6 hrs
• C. 5.5 hrs
• D. 6.5 hrs

Answer 1

Answer: (A)

5 hrs

Answer 2

CaC₂ + 2H₂O ® Ca(OH)₂ + C₂H₂

640/64=10 mole 10 mole

V =$\frac{nRT}{P}$=$\frac{10 \times 0.0821 \times 300}{1}$= 250 L