Question
Question: Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of \(1...
Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 10.0g. Silver has 47 electrons per atom, and its molar mass is 107.87gmol−1.
A. 2.62×1024
B. 5.24×1024
C. 7.62×1024
D. 1.62×1024
Solution
Firstly, find the number of moles in 10 g of silver by dividing the given mass by atomic mass of silver. After that on multiplying Avogadro constant find the total number of atoms that a mass of 10 gm of silver contain and then according to property of silver calculate the total number of electrons by multiplying the total number of atom with 47 as one neutral atom contain 47 electrons in it.
Complete step by step answer:
According to initial data we have,
Mass of silver pin (m) = 10.0 g
Number of electrons per atom = 4
Molar mass of a silver atom = 107.87gmol−1
Now, by using the formula of moles
n=Mm
Where
n= number of moles
m= given mass of silver pin
M= Molar mass of silver
On putting values in equation we have
n=108.7gmol−110g
n=108.710mole
Now, using the formula of the number of atoms per mol.
N=n×NA
Where
n=moles
N= number of atoms
NA= Avogadro constant which is equal to 6.023 × 1023
Putting values in above equation
N=107.8710×6.023×1023
On solving we get
N=5.58×1022
Total number of electrons = (number of electrons per atom) × (number of atoms)
Total number of electron = 47×N
On putting the values we get
Total number of electrons =47×5.58×1022
On further solving we get
Total number of electrons = 2.62×1024
Therefore Option (A) is correct.
Note: Be careful while calculating number of moles and atoms from moles. One mole of a substance is equal to 6.023×1023 units of that substance (such as atoms, molecules, or ions).
The number 6.023×1023 is known as Avogadro's number or Avogadro's constant. The concept of the mole can be used to convert between mass and number of particles.