Question
Question: Calculate the mole fraction of methanol in the vapor phase at \( {63.5^0}C \) for an ideal solution ...
Calculate the mole fraction of methanol in the vapor phase at 63.50C for an ideal solution containing 25.0g of pure methanol and 75.0g of pure ethanol?
Some data necessary to solve this:
Methanol MM is 32.0gmol−1
Vapor pressure is 717.2orr
Ethanol MM is 46.1gmol−1
Vapor pressure is 400.0torr
Solution
The number of moles of methanol, and ethanol will be calculated from their masses and molar masses. The mole fraction of methanol, and ethanol will be calculated from the moles of ethanol, methanol and total moles. The pressure of methanol and ethanol can be calculated from pressure given and mole fraction. The mole fraction of methanol at vapor pressure can be determined from the ratio of pressure of methanol to total pressure.
Complete answer:
The amount of methanol is 25g and molar mass of methanol is 32gmol−1
Moles of methanol will be nMeOH=3225=0.78125moles
The amount of ethanol is 75g and molar mass of methanol is 46gmol−1
Moles of methanol will be nEtOH=4675=1.6269moles
Total moles of methanol and ethanol will be 0.78125+1.6269=2.40815moles
Mole fraction of Methanol will be χMeOH=2.408150.78125=0.3244
Mole fraction of ethanol will be χEtOH=2.408151.6269=0.6756
According to Rouault’s law,
Psolution=χ.P0
The pressure of methanol will be PMeOH=0.3244×717.2torr=232.66torr
The pressure of ethanol will be PEtOH=0.6756×400torr=270.24torr
The total pressure will be 232.66+270.24=502.9torr
The mole fraction of methanol in vapour phase can be calculated from the ratio of the pressure of methanol total pressure.
χMeOHVapor=502.9232.66=0.463
Thus, the mole fraction of methanol in vapor phase is 0.463 .
Note:
The mole fraction is the ratio of moles of solute to the total moles of solute and solvent. It has no units. The mole fraction of solute is different from the mole fraction of solute in the vapor pressure. Mole fraction in the vapor phase means the ratio of pressure of methanol and total pressure.