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Question: Calculate the mode of the following data: Marks| \(10 - 15\)| \(15 - 20\)| \(20 - 25\)| \(25 - 3...

Calculate the mode of the following data:

Marks101510 - 15152015 - 20202520 - 25253025 - 30303530 - 35354035 - 40404540 - 45455045 - 50
Number of students448818183030202010105522
Explanation

Solution

First of all we need to find the modal class which is that interval whose frequency is maximum and the mode is given by the formula
mode=l+(ff12ff1f2)h{\text{mode}} = l + \left( {\dfrac{{f - {f_1}}}{{2f - {f_1} - {f_2}}}} \right)h
Here ll is the lower limit of the modal class and ff is the frequency of the modal class and f1{f_1} is the preceding frequency of the modal class interval and similarly the succeeding one is f2{f_2} and hh is the class size.

Complete step by step solution:
So here we are given that which class interval represents the marks earned by the number of students which is termed as the frequency and we need to calculate the mode. So basically mode is the value which appears the maximum time in the set of the observations. For example: if we have the set of the observations like 1,1,2,3,4,4,4,41, 1, 2, 3, 4, 4, 4, 4 so here 44 appears most of the time so it will be the mode of the given set of the observations.
Similarly we are given the set of the observations like

Marks101510 - 15152015 - 20202520 - 25253025 - 30303530 - 35354035 - 40404540 - 45455045 - 50
Number of students448818183030202010105522

So here number of maximum items is 3030 and this belongs to the class interval 253025 - 30
So here we can say that mode lies in the interval 253025 - 30
mode=l+(ff12ff1f2)h{\text{mode}} = l + \left( {\dfrac{{f - {f_1}}}{{2f - {f_1} - {f_2}}}} \right)h
Here ll is the lower limit of the modal class which is l=25l = 25 and ff is the frequency of the modal class which is 3030 and f1{f_1} is the preceding frequency of the modal class interval which is 1818and similarly the succeeding one is f2{f_2}which is 2020 and hh is the class size which is h=5h = 5
mode=l+(ff12ff1f2)h{\text{mode}} = l + \left( {\dfrac{{f - {f_1}}}{{2f - {f_1} - {f_2}}}} \right)h
mode=25+(3018601820)5=27.73{\text{mode}} = 25 + \left( {\dfrac{{30 - 18}}{{60 - 18 - 20}}} \right)5 = 27.73

So here the mode is 27.7327.73

Note:
Means are the averages of the given data, median is the central value of the data set and mode is the number which has appeared most of the time in the data set. So these three terms are related by the formula:
mode=3median2mean{\text{mode}} = 3{\text{median}} - 2{\text{mean}}
If any two of the above values are given then we can find the third value easily by using this formula.