Question

Calculate the mass of sodium acetate $(\text{CH}_3\text{COONa})$ required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is $82.0245\, \text{g mol}^{–1}.$

Answer 1

0.375 M aqueous solution of sodium acetate
= 1000 mL of solution containing 0.375 moles of sodium acetate
∴Number of moles of sodium acetate in 500 mL

$= \frac{0.375 }{ 1000} × 500$

= 0.1875 mole
Molar mass of sodium acetate = $82.0245\, \text{g mole}^{-1}$ (Given)
∴ Required mass of sodium acetate $=82.0245\, \text{g mole}^{-1}$ $(0.1875\ \text{mole})$
= 15.38 g